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Circular Drive Shaft Torsional Shear Stress (Mechanical Engineering)

A mechanical design engineer at the UNLV Howard R. Hughes College of Engineering is analyzing the torsional load capacity of a solid alloy steel drive shaft powering an industrial centrifugal water chiller.

The drive shaft has a circular cross-section of radius R=3 cmR = 3\text{ cm}. When transmitted engine torque twists the shaft, internal elastic torsional shear stress τ\tau develops. According to the mechanics of materials elastic torsion formula, shear stress varies directly with radial distance from the central rotational axis, modeled in Cartesian coordinates as:

τ(x,y)=12x2+y2[Newtons per square centimeter, N/cm2]\tau(x, y) = 12\sqrt{x^2 + y^2} \quad [\text{Newtons per square centimeter, N/cm}^2]
where x2+y2≤9x^2 + y^2 \le 9.

To evaluate the total internal resisting torque TT developed across the shaft cross-section, the engineer must integrate the moment of shear stress (dT=r⋅τ dAd T = r \cdot \tau \, dA) over the circular domain DD:

T=∬Dx2+y2⋅τ(x,y) dAT = \iint_D \sqrt{x^2 + y^2} \cdot \tau(x, y) \, dA

  1. Define the circular domain of integration DD in polar coordinates with radial bounds rr and angular limits θ\theta.
  2. Transform the torque integrand into polar coordinates, incorporating the Jacobian area differential dA=r dr dθdA = r \, dr \, d\theta.
  3. Evaluate the double integral to determine the total internal resisting torque TT in Newton-centimeters (N⋅cm\text{N}\cdot\text{cm}) and convert to Newton-meters (N⋅m\text{N}\cdot\text{m}).
  4. Explain how this polar integral relates to the polar moment of inertia JJ and prevents torsional shearing yield failure in rotating machinery drivetrains.