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Infinite Discontinuity

Core Definition

A function f(x)f(x) has an infinite discontinuity at x=cx = c if one or both of the one-sided limits grow without bound towards positive or negative infinity:

lim⁡x→c−f(x)=±∞orlim⁡x→c+f(x)=±∞\lim_{x \to c^-} f(x) = \pm\infty \quad \text{or} \quad \lim_{x \to c^+} f(x) = \pm\infty
Geometrically, this means the line x=cx = c is a vertical asymptote for the graph of f(x)f(x).

Concept Explanation

At an infinite discontinuity, the function exhibits unbounded behavior. As xx pinches closer to cc, the output values shoot infinitely high (+∞+\infty) or infinitely deep (−∞-\infty).

        y ^        | (Vertical Asymptote x = c)
          |        |
          |  |     |     |
          |  |     |     |
          |  \     |     /
          |   \    |    /
          +----+---+---+----------> x
               |   c   |

Because infinity is not a real number, any limit yielding ±∞\pm\infty fails to exist in the real numbers (DNE\text{DNE}).


Algebraic Hallmarks: k0\frac{k}{0} vs 00\frac{0}{0}

When evaluating limits of rational functions by direct substitution:

  • 00\frac{0}{0} (Indeterminate): Indicates a Removable Discontinuity (hole) that can be factored and canceled.
  • k0\frac{k}{0} with k≠0k \neq 0 (Undefined / Asymptote): Indicates an Infinite Discontinuity (vertical asymptote). The expression cannot be canceled; you must analyze the sign using Strategies for One-Sided Limits (the "positive and negative zero" approach).

Example Problems

Example Problem 1: Two-Sided Asymptote Analysis

Evaluate the one-sided and two-sided limits for:

f(x)=1x−3f(x) = \frac{1}{x - 3}

Solution

Step 1: Left-hand limit (x→3−x \to 3^-)
As x→3x \to 3 from the left (x<3x < 3), x−3x - 3 is a tiny negative decimal (0−0^-):

lim⁡x→3−1x−3=10−=−∞\lim_{x \to 3^-} \frac{1}{x - 3} = \frac{1}{0^-} = -\infty

Step 2: Right-hand limit (x→3+x \to 3^+)
As x→3x \to 3 from the right (x>3x > 3), x−3x - 3 is a tiny positive decimal (0+0^+):

lim⁡x→3+1x−3=10+=+∞\lim_{x \to 3^+} \frac{1}{x - 3} = \frac{1}{0^+} = +\infty

Step 3: Two-sided limit and classification
Since the one-sided limits blow up to opposite infinities, lim⁡x→3f(x)=DNE\lim_{x \to 3} f(x) = \text{DNE}. f(x)f(x) has an infinite discontinuity with vertical asymptote x=3x = 3.

Example Problem 2: Even Power Vertical Asymptote

Evaluate the limit:

lim⁡x→25(x−2)2\lim_{x \to 2} \frac{5}{(x - 2)^2}

Solution

Step 1: Check denominator behavior from both sides
As x→2x \to 2 from either side (x→2−x \to 2^- or x→2+x \to 2^+), (x−2)2(x - 2)^2 is squared, so it is strictly positive and approaches 00 (0+0^+).

Step 2: Evaluate the limit

lim⁡x→25(x−2)2=50+=+∞\lim_{x \to 2} \frac{5}{(x - 2)^2} = \frac{5}{0^+} = +\infty

Conclusion: f(x)f(x) has an infinite discontinuity at x=2x = 2, where both sides shoot upward to +∞+\infty.


Connections & References