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Robotic Arm Path Planning (Mechanical & Aerospace Engineering) Solution

In robotics, the forward kinematics function maps the joint angles of a robotic arm to a physical coordinate (x,y)(x, y) in space. However, to control the robot, engineers must solve the inverse kinematics problem: given a target coordinate (x,y)(x, y), calculate the joint angle θ\theta required to reach it.

For a single-link arm of length L=5 unitsL = 5\text{ units}, the position is given by x=5cosθx = 5\cos\theta and y=5sinθy = 5\sin\theta.

  1. Reconstruct the trigonometric relationship to show that θ=arctan(yx)\theta = \arctan\left(\frac{y}{x}\right).
  2. If the arm needs to target the coordinate (x,y)=(3,4)(x, y) = (-3, 4) in Quadrant II, evaluate the joint angle θ\theta in radians, accounting for quadrant corrections.

Step-by-Step Solution:

  1. Using the given coordinates:
    yx=5sinθ5cosθ=tanθ\frac{y}{x} = \frac{5\sin\theta}{5\cos\theta} = \tan\theta
    Taking the inverse tangent of both sides:
    θ=arctan(yx)\theta = \arctan\left(\frac{y}{x}\right)
  2. For (x,y)=(3,4)(x, y) = (-3, 4):
    θref=arctan(43)=arctan(43)0.927 rad\theta_{\text{ref}} = \arctan\left(\left|\frac{4}{-3}\right|\right) = \arctan\left(\frac{4}{3}\right) \approx 0.927\text{ rad}
    Since x<0x < 0 and y>0y > 0, the target lies in Quadrant II. The true angle θ\theta is:
    θ=πθref=πarctan(43)3.1420.927=2.215 rad\theta = \pi - \theta_{\text{ref}} = \pi - \arctan\left(\frac{4}{3}\right) \approx 3.142 - 0.927 = 2.215\text{ rad}

Meaning of the Answer & Real-Life Application:

Standard inverse trigonometric functions like arctan(z)\arctan(z) are mathematically restricted to Quadrants I and IV ((π2,π2)(-\frac{\pi}{2}, \frac{\pi}{2})). In robotics and path planning, software engineers use quadrant dynamics to reconstruct the true angle in 2D space (often using functions like atan2(y, x)) to prevent the arm from moving to the incorrect mirror-image location.