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Structural Stress Analysis in Spherical Joints Solution

In civil and mechanical structural engineering, large-span space frame roofs and pedestrian bridges rely on solid spherical cast-steel node joints to anchor converging diagonal structural struts. Under combined tension, compression, and shear loads from bridge traffic and wind gusts, a 3D internal stress tensor field develops inside each spherical node.

A structural engineering research team at UNLV models the equivalent Von Mises stress distribution σ\sigma (in megapascals, MPa\text{MPa}) inside a solid spherical steel support joint of radius R=5 cmR = 5\text{ cm} using the three-variable radical function:

σ=h(x,y,z)=5025−(x2+y2+z2)\sigma = h(x, y, z) = 50\sqrt{25 - (x^2 + y^2 + z^2)}
where x,y,zx, y, z represent spatial coordinates (in centimeters) measured from the geometric center core of the node (0,0,0)(0, 0, 0).

An ultrasonic nondestructive evaluation (NDE) transducer inspects internal material properties at the coordinate point (3,4,2)(3, 4, 2).

  1. State the algebraic domain condition for h(x,y,z)h(x, y, z) and write the mathematical domain DD in set-builder notation. Describe the geometric 3D solid region it represents.
  2. Determine the mathematical range RR of the stress function in interval notation. Identify the coordinates where maximum stress occurs and where stress drops to zero.
  3. Evaluate whether the inspection point (3,4,2)(3, 4, 2) lies within the physical material domain of the steel joint. Explain the engineering significance of this result for structural inspection workflows.

Step-by-Step Solution:

  1. State the Domain Condition and Classify 3D Volume: State the Radicand Non-Negativity Condition for Three-Variable Functions:

    25−(x2+y2+z2)≥025 - (x^2 + y^2 + z^2) \ge 0
    Rearranging terms:
    x2+y2+z2≤25x^2 + y^2 + z^2 \le 25

    • Set-Builder Notation:
      D={(x,y,z)∈R3∣x2+y2+z2≤25}D = \{(x, y, z) \in \mathbb{R}^3 \mid x^2 + y^2 + z^2 \le 25\}
    • Geometric Description: The domain represents a solid 3D sphere (a closed ball) centered at the origin (0,0,0)(0, 0, 0) with a boundary radius of R=25=5 cmR = \sqrt{25} = 5\text{ cm}.
    • Topological Classification: Because the domain includes its outer spherical boundary surface x2+y2+z2=25x^2 + y^2 + z^2 = 25, it is a closed and bounded solid volume in R3\mathbb{R}^3. (Defined in Domain and Range of Multivariable Functions.)
  2. Determine the Stress Range: State the Three-Variable Quadratic Extremum Formulation: The radial distance squared from the center is ρ2=x2+y2+z2≥0\rho^2 = x^2 + y^2 + z^2 \ge 0.

    • Maximum Stress (ρ=0\rho = 0): At the geometric center core (0,0,0)(0, 0, 0), ρ2=0\rho^2 = 0:
      σmax⁡=h(0,0,0)=5025−0=50(5)=250 MPa\sigma_{\max} = h(0, 0, 0) = 50\sqrt{25 - 0} = 50(5) = 250\text{ MPa}
    • Minimum Stress (ρ=5\rho = 5): Along the entire outer spherical shell x2+y2+z2=25x^2 + y^2 + z^2 = 25:
      σmin⁡=5025−25=0 MPa\sigma_{\min} = 50\sqrt{25 - 25} = 0\text{ MPa}
    • Range in Interval Notation:
      R=[0,250] MPaR = [0, 250]\text{ MPa}
  3. Evaluate Inspection Coordinate Point (3,4,2)(3, 4, 2): Compute the distance squared from the origin to the inspection point:

    ρ2=x2+y2+z2=32+42+22=9+16+4=29\rho^2 = x^2 + y^2 + z^2 = 3^2 + 4^2 + 2^2 = 9 + 16 + 4 = 29
    Test the domain inequality:
    29≤25(False, since 29>25)29 \le 25 \quad \text{(False, since } 29 > 25\text{)}
    Substituting into the mathematical function yields:
    σ=5025−29=50−4=100i∉R\sigma = 50\sqrt{25 - 29} = 50\sqrt{-4} = 100i \notin \mathbb{R}
    The point (3,4,2)(3, 4, 2) is located at distance ρ=29≈5.385 cm>5 cm\rho = \sqrt{29} \approx 5.385\text{ cm} > 5\text{ cm} from the center, placing it strictly outside the steel joint.

Meaning of the Answer & Real-Life Application:

The point (3,4,2)(3, 4, 2) lies in ambient open air 0.385 cm0.385\text{ cm} beyond the spherical metal casing. Evaluating the stress formula generates an imaginary number, signifying that the physical continuum model is non-existent beyond the outer steel surface. In automated NDE robotics, domain-checking algorithms prevent scanner arms from hunting for internal echoes outside the workpiece boundary, preventing false defect alerts and calibration faults during structural inspections.