🌱 Tony's Memex Tony's Intertwingled Memex
Digital Garden | OER Curriculum
Home / Digital Garden / Terrain Surveying & Road Grade Safety Solution

Terrain Surveying & Road Grade Safety Solution

In civil and transportation engineering, route alignment across mountainous topography requires rigorous analysis of surveyed ground elevation models. Before heavy earthmoving equipment and drilling rigs can be deployed to cut roadway grades, geotechnical engineers must establish the exact spatial boundaries of the mathematical elevation model to ensure equipment is never dispatched into unmapped or physically invalid zones.

A civil engineering survey team at UNLV models the localized terrain elevation zz (measured in hundreds of meters above a base datum) for a proposed mountain bypass using the multivariable radical function:

z=f(x,y)=16−x2−y2z = f(x, y) = \sqrt{16 - x^2 - y^2}
where xx and yy represent surveyed horizontal grid coordinates (in kilometers) measured east and north from a base transit station.

A planned construction access corridor requires heavy excavation machinery to traverse the regional grid point (3,2)(3, 2).

  1. State the algebraic domain condition for f(x,y)f(x, y) and determine the mathematical domain DD in set-builder notation. Describe its geometric boundary and classify the region as open or closed, and bounded or unbounded.
  2. Determine the mathematical range RR of the elevation function in interval notation, identifying the maximum mountain peak elevation and the perimeter base elevation in physical units (meters).
  3. Evaluate whether the proposed construction access point (3,2)(3, 2) lies within the valid terrain domain. Explain what this result means for project safety and heavy equipment operations.

Step-by-Step Solution:

  1. Determine the Mathematical Domain and Topological Classification: State the Radicand Non-Negativity Condition for Multivariable Radical Functions:

    16−x2−y2≥016 - x^2 - y^2 \ge 0
    Rearranging terms yields:
    x2+y2≤16x^2 + y^2 \le 16

    • Set-Builder Notation:
      D={(x,y)∈R2∣x2+y2≤16}D = \{(x, y) \in \mathbb{R}^2 \mid x^2 + y^2 \le 16\}
    • Geometric Description: The domain is a closed circular disk of radius r=16=4 kmr = \sqrt{16} = 4\text{ km} centered at the base station (0,0)(0, 0).
    • Classification: Because the region contains its entire circular boundary curve x2+y2=16x^2 + y^2 = 16 (non-strict inequality ≤\le), it is closed. Because the entire disk lies within a finite radius of 4 km4\text{ km}, it is bounded. (Defined in Domain and Range of Multivariable Functions.)
  2. Determine the Elevation Range: State the Extremal Value Analysis for Bounded Quadratic Radicands: The quantity x2+y2x^2 + y^2 attains its minimum value of 00 at the origin (0,0)(0, 0):

    zmax⁡=f(0,0)=16−0=4 (in hundreds of meters)  ⟹  400 metersz_{\max} = f(0, 0) = \sqrt{16 - 0} = 4\text{ (in hundreds of meters)} \implies 400\text{ meters}
    The quantity x2+y2x^2 + y^2 attains its maximum value of 1616 along the perimeter boundary x2+y2=16x^2 + y^2 = 16:
    zmin⁡=16−16=0 metersz_{\min} = \sqrt{16 - 16} = 0\text{ meters}

    • Range in Interval Notation:
      R=[0,4]R = [0, 4]
      In physical elevation units, the terrain elevation spans from 0 m0\text{ m} at the outer survey perimeter to a peak summit of 400 m400\text{ m} directly above the base transit station.
  3. Evaluate Proposed Access Point (3,2)(3, 2): Substitute x=3x = 3 and y=2y = 2 into the domain condition:

    x2+y2=32+22=9+4=13x^2 + y^2 = 3^2 + 2^2 = 9 + 4 = 13
    Check against the boundary limit:
    13≤16(True)13 \le 16 \quad \text{(True)}
    Because 13<1613 < 16, the point (3,2)(3, 2) lies strictly within the interior of the domain disk. Evaluating the actual elevation:
    z=f(3,2)=16−32−22=16−13=3≈1.732 hundreds of meters  ⟹  173.2 metersz = f(3, 2) = \sqrt{16 - 3^2 - 2^2} = \sqrt{16 - 13} = \sqrt{3} \approx 1.732\text{ hundreds of meters} \implies 173.2\text{ meters}

Meaning of the Answer & Real-Life Application:

Because the coordinate (3,2)(3, 2) satisfies the domain condition (x2+y2=13≤16x^2 + y^2 = 13 \le 16), it represents a physically real, accessible location on the hillside at an elevation of 173.2 m173.2\text{ m}. Had the coordinate evaluation yielded x2+y2>16x^2 + y^2 > 16, the radicand would be negative, indicating a point outside the surveyed topography where the mathematical model breaks down (e.g., dropping off a cliff or extending beyond the project survey boundary). Confirming domain containment ensures that earthmoving contractors can safely grade access roads without navigating off-grid drop-offs.